-24x^2+7x+6=0

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Solution for -24x^2+7x+6=0 equation:



-24x^2+7x+6=0
a = -24; b = 7; c = +6;
Δ = b2-4ac
Δ = 72-4·(-24)·6
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-25}{2*-24}=\frac{-32}{-48} =2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+25}{2*-24}=\frac{18}{-48} =-3/8 $

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